x^2+16x+13=0

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Solution for x^2+16x+13=0 equation:


Simplifying
x2 + 16x + 13 = 0

Reorder the terms:
13 + 16x + x2 = 0

Solving
13 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + 16x + -13 + x2 = 0 + -13

Reorder the terms:
13 + -13 + 16x + x2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 16x + x2 = 0 + -13
16x + x2 = 0 + -13

Combine like terms: 0 + -13 = -13
16x + x2 = -13

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -13 + 64

Reorder the terms:
64 + 16x + x2 = -13 + 64

Combine like terms: -13 + 64 = 51
64 + 16x + x2 = 51

Factor a perfect square on the left side:
(x + 8)(x + 8) = 51

Calculate the square root of the right side: 7.141428429

Break this problem into two subproblems by setting 
(x + 8) equal to 7.141428429 and -7.141428429.

Subproblem 1

x + 8 = 7.141428429 Simplifying x + 8 = 7.141428429 Reorder the terms: 8 + x = 7.141428429 Solving 8 + x = 7.141428429 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 7.141428429 + -8 Combine like terms: 8 + -8 = 0 0 + x = 7.141428429 + -8 x = 7.141428429 + -8 Combine like terms: 7.141428429 + -8 = -0.858571571 x = -0.858571571 Simplifying x = -0.858571571

Subproblem 2

x + 8 = -7.141428429 Simplifying x + 8 = -7.141428429 Reorder the terms: 8 + x = -7.141428429 Solving 8 + x = -7.141428429 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -7.141428429 + -8 Combine like terms: 8 + -8 = 0 0 + x = -7.141428429 + -8 x = -7.141428429 + -8 Combine like terms: -7.141428429 + -8 = -15.141428429 x = -15.141428429 Simplifying x = -15.141428429

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.858571571, -15.141428429}

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